fixed main

content/index.md

@@ -3,7 +3,3 @@ title: Welcome to the Warehouse
 ---
 Welcome to the warehouse of the Thoughts of 0x6d617273756c746f72, Prime of the Faith, ranked Hacker on HTB, and the founder of a bunch of defunct projects on github. Average internet nerd/sysadmin/programmer. Move on, to either his cursed musings or with your day.
 
-# Socials
-
-- Matrix: [@lanre:envs.net](https://matrix.to/#/@lanre:envs.net)
-- Bluesky: [krishna.ayyalasomayajula.net](https://bsky.app/profile/krishna.ayyalasomayajula.net)

content/physics/CrazyStuff.md

@@ -0,0 +1,192 @@
+---
+title: Crazy Mix of Everything You Could Dread
+date: 2025-02-15
+---
+
+# Electric Charge and Electric Field
+
+## Laws?
+
+1. *Law of Conservation of Electric Charge*: **the net amount of electric charge produced in any process is zero**.
+
+2. I forgot
+
+## Insulators and Conductors
+
+This image should sum things up nicely.
+
+![](swappy-20250215-165128.png)
+
+## Coulomb's Law 
+
+$$
+||\vec{F}||=k\frac{Q_1 Q_2}{r^2}
+$$
+
+$k$ is a random constant written in terms of a more definite constant such that:
+
+$$
+F=\frac{1}{r\pi\epsilon_0}\frac{Q_1 Q_2}{r_2}
+$$
+where
+$$
+\epsilon_0=\frac{1}{4\pi k}=8.85\times 10^{-12}\;\text{ C}^2/\mathrm{N}*\mathrm{m}^2
+$$
+
+It's important to consider here, that $r$ is the magnitude of distance, and $F$ always represents the magnitude of the force. Oppositely signed charges attract, and same-signed charges repel with the force computed by the formula.
+
+# The Electric Field 
+
+$$
+\vec{E}=\frac{\vec{F}}{q}
+$$
+
+- $q$ is the magnitude of the charge 
+- The electric field only reflects the *direction* of the magnetic field, not the intensity.
+- The electric field $\vec{E}$ represents the force per unit charge, so really: 
+
+$$
+\vec{E}=\lim_{q\to 0}{\vec{F}/q}
+$$ 
+
+The electric field has the units Newtons per Coulomb: N/C. The magnitude of the electric field vector $\vec{E}$, can be calculated as $E$:
+$$
+E=\frac{F}{q}=\frac{kqQ/r^2}{q} = k\frac{Q}{r^2}
+$$
+
+
+Notice that the vector field $\vec{E}$ is independent of the test charge $q$, only dependent on the parent charge $Q$ that produces the field. $\therefore$, the force experienced by a particle at a given position $r$ can be expressed by: 
+
+$$
+\vec{F}=q\vec{E}
+$$
+
+If there are more than one parent charge $Q$, the experienced electric vector field is simply: 
+
+$$
+\vec{E}=\vec{E_1}+\vec{E_2}+\vec{E_n}
+$$
+
+# Electric Potential Energy and Potential Difference 
+
+A fundamental law of physics is that $\Delta \textbf{PE} =-W$, while the change in kinetic energy is oppositely signed. The potential difference between any two points is $\textbf{PE}_b-\textbf{PE}_a$, while work is expressed like so:
+
+$$
+W=\int{F\mathrm{d}r}
+$$
+
+> [!NOTE]
+> $r$ and $x$ are used interchangeably for displacement. $r$ is more commonly seen in multi-dimensional reference frames.
+
+$\therefore$ the work done by electric field $\vec{E}$ is:
+
+$$
+W=Fd=-qEd
+$$
+$$\Delta \textbf{PE}=-qEd 
+$$
+
+This is only true if the electric field is uniform. In reality, it never is.
+
+## Potential Difference 
+
+**Electric Potential** is understood as the electric potential energy per unit charge. This variable is given the symbol $V$. At some displacement $a$ from the parent charge $Q$:
+
+$$
+V_a=\frac{\textbf{PE}_a}{q}
+$$
+
+Two balls at the same height are not meaningfully different in position, therefore only *potential difference* matters physically. In this case, between two points, $a$ and $b$. When the electric force does positive work on a charge, the kinetic energy increases in tandem with a decrease of that potential difference. Keeping in line with the rules laid out above:
+
+$$
+V_{ba}=V_b-V_a=\frac{\Delta \textbf{PE}_{ba}}{q}=\frac{-W_{ba}}{q}
+$$
+
+Just as the potential energy of a raised ball does not depend on the gravitational field of the ball, the electric potential of the test charge $q$ doesn't depend on the magnitude of the charge itself. This quantity is given the unit **Volt**, or $1\text{ V}=1\;\text{J}/\mathrm{C}$ 
+
+# Circuits
+### Ohm’s Law:
+$$
+V = IR
+$$
+- Voltage $V$ = Current $I$ × Resistance $R$
+
+### Power in Circuits:
+$$
+P = IV
+$$
+- Power $P$ = Current $I$ × Voltage $V$
+
+$$
+P = I^2R
+$$
+- Power $P$ = Current squared $I^2$ × Resistance $R$
+
+$$
+P = \frac{V^2}{R}
+$$
+- Power $P$ = Voltage squared $V^2$ / Resistance $R$
+
+### Series Circuits:
+$$
+R_{\text{total}} = R_1 + R_2 + \dots + R_n
+$$
+- Total Resistance $R_{\text{total}}$ = Sum of Individual Resistances
+
+$$
+V_{\text{total}} = V_1 + V_2 + \dots + V_n
+$$
+- Total Voltage $V_{\text{total}}$ = Sum of Individual Voltages
+
+$$
+I_{\text{total}} = I_1 = I_2 = \dots = I_n
+$$
+- Current $I_{\text{total}}$ is the same across all components
+
+### Parallel Circuits:
+$$
+\frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \dots + \frac{1}{R_n}
+$$
+- Total Resistance $R_{\text{total}}$ = Reciprocal Sum of Individual Resistances
+
+$$
+V_{\text{total}} = V_1 = V_2 = \dots = V_n
+$$
+- Voltage $V_{\text{total}}$ is the same across all components
+
+$$
+I_{\text{total}} = I_1 + I_2 + \dots + I_n
+$$
+- Total Current $I_{\text{total}}$ is the sum of individual currents
+
+### Capacitance:
+$$
+Q = CV
+$$
+- Charge $Q$ = Capacitance $C$ × Voltage $V$
+
+$$
+C = \frac{\epsilon_0 A}{d}
+$$
+- Capacitance $C$ of a parallel plate capacitor: $\epsilon_0$ = permittivity of free space, $A$ = area of plates, $d$ = distance between plates
+
+### Inductance:
+$$
+V = L \frac{di}{dt}
+$$
+- Voltage across an inductor $V$ = Inductance $L$ × Rate of change of current $\frac{di}{dt}$
+
+### RL Time Constant:
+$$
+\tau = \frac{L}{R}
+$$
+- Time constant $\tau$ for an RL circuit
+
+### Kirchhoff’s Laws:
+- **Kirchhoff’s Current Law (KCL):** The sum of currents entering a junction equals the sum of currents leaving.
+- **Kirchhoff’s Voltage Law (KVL):** The sum of voltages around any closed loop equals zero.
+
+
+
+---
+#physics

content/physics/final.md

@@ -0,0 +1,101 @@
+> [!NOTE] A mass $m$ attached to a spring with constant $k$ oscillates on a frictionless surface. Derive an expression for the velocity $v$ as a function of displacement $x$.
+>
+> [!INFO]-
+> Total mechanical energy in SHM is conserved:
+> $$
+> E = \frac{1}{2}mv^2 + \frac{1}{2}kx^2 = \frac{1}{2}kA^2
+> $$
+> Solving for $v$:
+> $$
+> v = \pm \sqrt{\frac{k}{m}(A^2 - x^2)}
+> $$
+
+> [!NOTE] A wave traveling along a rope is represented by $y(x,t) = 0.02\cos(40x - 600t)$. Determine the amplitude, wavelength, frequency, and speed of the wave.
+>
+> [!INFO]-
+> The general wave form is $y = A\cos(kx - \omega t)$:
+> - Amplitude $A = 0.02\ \mathrm{m}$
+> - Wave number $k = 40 \Rightarrow \lambda = \frac{2\pi}{k} = \frac{2\pi}{40} = 0.157\ \mathrm{m}$
+> - Angular frequency $\omega = 600 \Rightarrow f = \frac{\omega}{2\pi} = \frac{600}{2\pi} \approx 95.5\ \mathrm{Hz}$
+> - Wave speed $v = f\lambda = 95.5 \times 0.157 \approx 15\ \mathrm{m/s}$
+
+> [!NOTE] In Young's double slit experiment, fringes are formed on a screen 1.2 m away using light of wavelength $600\ \text{nm}$. The slits are separated by $0.2\ \text{mm}$. Calculate the distance between adjacent bright fringes.
+>
+> [!INFO]-
+> Fringe spacing is given by:
+> $$
+> y = \frac{\lambda D}{d} = \frac{600 \times 10^{-9} \times 1.2}{0.2 \times 10^{-3}} = 3.6\ \text{mm}
+> $$
+
+> [!NOTE] A pendulum of length $0.5\ \mathrm{m}$ is displaced by a small angle. Determine its period and explain why amplitude does not affect the result.
+>
+> [!INFO]-
+> The period is:
+> $$
+> T = 2\pi\sqrt{\frac{L}{g}} = 2\pi\sqrt{\frac{0.5}{9.8}} \approx 1.41\ \mathrm{s}
+> $$
+> In the small-angle approximation ($\theta < 10^\circ$), motion is independent of amplitude.
+
+> [!NOTE] A charged particle $q$ moves through a uniform electric field $E$. Derive the expression for the work done on the charge and its change in potential energy.
+>
+> [!INFO]-
+> Work done:
+> $$
+> W = qEd
+> $$
+> Change in potential energy:
+> $$
+> \Delta U = -qEd
+> $$
+> since electric potential energy decreases when the charge moves in the direction of the field.
+
+> [!NOTE] A capacitor of $10\ \mu\mathrm{F}$ is charged to $5\ \mathrm{V}$. Calculate the energy stored in it.
+>
+> [!INFO]-
+> $$
+> E = \frac{1}{2}CV^2 = \frac{1}{2} \cdot 10 \times 10^{-6} \cdot 25 = 1.25 \times 10^{-4}\ \mathrm{J}
+> $$
+
+> [!NOTE] A coil of wire rotates in a magnetic field. Use Faraday’s law to derive the expression for the induced emf.
+>
+> [!INFO]-
+> Faraday’s law:
+> $$
+> \mathcal{E} = -\frac{d\Phi}{dt}
+> $$
+> Magnetic flux $\Phi = B A \cos(\omega t)$, so:
+> $$
+> \mathcal{E} = B A \omega \sin(\omega t)
+> $$
+
+> [!NOTE] A wire carries a current of $3\ \mathrm{A}$ through a magnetic field of $0.5\ \mathrm{T}$ perpendicular to its length. The wire is $0.4\ \mathrm{m}$ long. Find the magnetic force.
+>
+> [!INFO]-
+> $$
+> F = ILB\sin\theta = 3 \cdot 0.4 \cdot 0.5 \cdot 1 = 0.6\ \mathrm{N}
+> $$
+
+> [!NOTE] Explain the effect of damping on the amplitude-frequency graph of a driven harmonic oscillator.
+>
+> [!INFO]-
+> Damping reduces the peak amplitude and shifts the resonant frequency slightly lower. Greater damping broadens the curve and lowers the quality factor $Q$.
+
+> [!NOTE] A mass-spring oscillator experiences light damping. Write the differential equation and general solution.
+>
+> [!INFO]-
+> Equation:
+> $$
+> m\ddot{x} + b\dot{x} + kx = 0
+> $$
+> Solution:
+> $$
+> x(t) = A e^{-\gamma t} \cos(\omega' t + \phi)
+> $$
+> where $\gamma = \frac{b}{2m}$ and $\omega' = \sqrt{\omega_0^2 - \gamma^2}$.
+
+> [!NOTE] A $0.2\ \mathrm{kg}$ object experiences a force due to gravity from Earth at a distance of $6.4 \times 10^6\ \mathrm{m}$. Calculate the force.
+>
+> [!INFO]-
+> $$
+> F = G\frac{Mm}{r^2} = 6.67 \times 10^{-11} \cdot \frac{5.97 \times 10^{24} \cdot 0.2}{(6.4 \times 10^6)^2} \approx 1.96\ \mathrm{N}
+> $$

content/physics/harmonic-motion.md

@@ -250,9 +250,11 @@ $$
 ### **How to Calculate $ n $:**
 Since $ n $ counts both nodes and antinodes:
 $$
-n = \text{total nodes} + \text{total antinodes}
+n = \text{total nodes} + \text{total antinodes}-1
 $$
 
+The above is true only if you cound the starting node of the fixture of the air column. You do not subtract by $1$ otherwise.  
+
 ---
 
 ## **Both Ends Open (Pipe Open at Both Ends)**
@@ -289,3 +291,237 @@ $$
 | **Both Ends Open**          | Antinode at both ends        | $L = n \frac{\lambda}{2}$               | $f_n = \frac{n v}{2L}$   | $n = \text{antinodes}$ |
 
 Now the formulas **remain internally consistent with a fixed definition of $ n $** across all cases.
+
+# Pendulum formulas
+
+Here are the main pendulum formulas in general physics:
+
+1. **Period of a simple pendulum** (small angle approximation):
+   $$
+   T = 2\pi \sqrt{\frac{L}{g}}
+   $$
+   Where:
+   - $T$ = period (time for one full swing)
+   - $L$ = length of the pendulum
+   - $g$ = acceleration due to gravity
+
+2. **Frequency of a simple pendulum**:
+   $$
+   f = \frac{1}{T} = \frac{1}{2\pi} \sqrt{\frac{g}{L}}
+   $$
+   Where:
+   - $f$ = frequency (number of oscillations per second)
+
+3. **Angular frequency** of a simple pendulum:
+   $
+   \omega = \sqrt{\frac{g}{L}}
+   $
+   Where:
+   - $\omega$ = angular frequency (rad/s)
+
+4. **Displacement of a simple pendulum (for small angles)**:
+   $$
+   \theta(t) = \theta_0 \cos(\omega t)
+   $$
+   Where:
+   - $\theta(t)$ = angular displacement at time \(t\)
+   - $\theta_0$ = maximum displacement (amplitude)
+
+5. **Energy of a simple pendulum**:
+   - **Potential Energy** at maximum displacement:
+     $$
+     PE = mgh
+     $$
+     Where:
+     - $m$ = mass of the pendulum bob
+     - $h$ = height relative to the lowest point
+
+   - **Kinetic Energy** at the equilibrium point:
+     $$
+     KE = \frac{1}{2}mv^2
+     $$
+
+6. **Damped pendulum (under the influence of friction)**:
+   $$
+   \theta(t) = \theta_0 e^{-\gamma t} \cos(\omega t)
+   $$
+   Where:
+   - $\gamma$ = damping coefficient
+
+7. **For a physical pendulum** (a rigid body swinging about a pivot):
+   $$
+   T = 2\pi \sqrt{\frac{I}{mgd}}
+   $$
+   Where:
+   - $I$ = moment of inertia of the object
+   - $d$ = distance from the pivot point to the center of mass
+
+These are the key formulas for general pendulum motion, covering simple and physical pendulums, damped motion, and energy analysis.
+
+# Dampened Springs
+
+The damping coefficient, denoted by $\gamma$, quantifies the rate at which the amplitude of oscillation decreases over time due to resistive forces (like friction or air resistance) acting on the system. It depends on factors like the properties of the medium (air, fluid, etc.) and the characteristics of the object (shape, surface area, etc.).
+
+The damping force is typically modeled as:
+
+$$
+F_{\text{damping}} = -\gamma v
+$$
+
+where:
+- $F_{\text{damping}}$ is the damping force,
+- $\gamma$ is the damping coefficient, and
+- $v$ is the velocity of the oscillating mass.
+
+The damping coefficient influences how quickly the system loses energy. The larger the damping coefficient, the faster the oscillations decay.
+
+### Types of Damping:
+1. **Underdamped**: If the damping is weak ($\gamma < \omega_0$), the system still oscillates, but with decreasing amplitude. The system's motion is described by:
+
+   $$
+   x(t) = A e^{-\gamma t} \cos(\omega' t + \phi)
+   $$
+
+2. **Critically damped**: If the damping is strong enough to prevent oscillations, but not too strong to cause the system to return to equilibrium too slowly, we have the critical damping condition: $\gamma = \omega_0$.
+
+3. **Overdamped**: If the damping is too strong ($\gamma > \omega_0$), the system returns to equilibrium without oscillating, but more slowly than in the critically damped case.
+
+### Relation to Natural Frequency:
+The **damped angular frequency** $\omega'$ is related to the natural frequency $\omega_0$ by:
+
+$$
+\omega' = \sqrt{\omega_0^2 - \gamma^2}
+$$
+
+This shows that as $\gamma$ increases, $\omega'$ decreases, meaning the system oscillates less rapidly. If $\gamma$ is large enough (in the overdamped case), there will be no oscillations at all.
+
+In summary, the damping coefficient $\gamma$ plays a key role in determining the rate at which a mass-spring system loses energy and the nature of its oscillations.
+### Snell's Law:
+Snell's Law describes the relationship between the angles of incidence and refraction when a wave passes through the boundary between two media with different refractive indices. It is given by:
+
+$$
+n_1 \sin(\theta_1) = n_2 \sin(\theta_2)
+$$
+
+Where:
+- $n_1$ and $n_2$ are the refractive indices of the two media,
+- $\theta_1$ and $\theta_2$ are the angles of incidence and refraction, respectively, measured from the normal.
+
+Snell's Law explains how light bends when it transitions from one medium to another (e.g., air to water). If the refractive index increases (e.g., from air to glass), the light slows down and bends towards the normal. Conversely, if the refractive index decreases (e.g., from water to air), light bends away from the normal.
+
+### Doppler Effect:
+The Doppler Effect refers to the change in frequency (or wavelength) of a wave as observed by someone moving relative to the wave source. For sound waves, the observed frequency $f'$ is given by:
+
+$$
+f' = f \left( \frac{v \pm v_{\text{observer}}}{v \pm v_{\text{source}}} \right)
+$$
+
+Where:
+- $f'$ is the observed frequency
+- $f$ is the emitted frequency,
+- $v$ is the wave speed in the medium,
+- $v_{\text{observer}}$ is the velocity of the observer relative to the medium,
+- $v_{\text{source}}$ is the velocity of the source relative to the medium.
+
+The sign conventions depend on whether the observer and source are moving towards or away from each other:
+- Moving towards each other: use the "+" sign in the numerator and the "-" in the denominator.
+- Moving apart: use the "-" sign in the numerator and the "+" in the denominator.
+
+In the case of light, the relativistic Doppler shift formula is used, where the frequency shift is influenced by both the motion and the speed of light.
+
+The Doppler Effect explains phenomena such as the change in pitch of a passing car or the redshift/blueshift observed in the light from stars and galaxies.
+Sure! Here's a combined explanation of the **path difference** in the double-slit experiment, with the math expressed using LaTeX notation:
+
+---
+# Young's Experiment
+In the **double-slit experiment**, light passes through two slits and creates an interference pattern on a screen. The **path difference** refers to the difference in the distances that the light waves travel from each of the two slits to a particular point on the screen.
+
+### What is Path Difference?
+
+1. **Two light waves** are emitted from the two slits, and they travel towards a point on the screen.
+2. The distance traveled by the light from the first slit to that point is different from the distance traveled by the light from the second slit.
+3. The **path difference** is simply the difference between these two distances.
+
+### How Path Difference Affects the Interference Pattern:
+
+- **Constructive Interference**: This occurs when the path difference is a **whole number multiple** of the wavelength, i.e.,
+
+  $$ 
+  \Delta y = m\lambda \quad \text{(where $m$ is an integer)} 
+  $$
+
+  In this case, the waves arrive **in phase** and interfere **constructively**, creating a **bright fringe** on the screen.
+
+- **Destructive Interference**: This happens when the path difference is an **odd multiple** of half the wavelength, i.e.,
+
+  $$ 
+  \Delta y = \left( m + \frac{1}{2} \right) \lambda \quad \text{(where $m$ is an integer)} 
+  $$
+
+  Here, the waves arrive **out of phase** and interfere **destructively**, resulting in a **dark fringe**.
+
+### Formula for Path Difference:
+
+In the double-slit experiment, the path difference for a point on the screen at an angle \( \theta \) can be expressed as:
+
+$$
+\Delta y = d \sin \theta
+$$
+
+Where:
+- $ \Delta y $ = path difference
+- $ d $ = distance between the two slits
+- $ \theta $ = angle between the central maximum (the center of the pattern) and the point on the screen
+- $ \lambda $ = wavelength of the light
+
+At the **central maximum** (the middle bright fringe), the path difference is zero because the light from both slits travels the same distance. As you move away from the center, the path difference increases, affecting the type of interference (constructive or destructive) at each point on the screen.
+
+### How Path Difference Relates to Intensity:
+
+The intensity of the light at a point on the screen in the double-slit experiment depends on the path difference. The intensity for constructive and destructive interference can be written as:
+
+For constructive interference (bright fringes):
+
+$$
+I_m = I_0 \cos^2\left(\frac{m\pi d}{\lambda D}\right)
+$$
+
+For destructive interference (dark fringes):
+
+$$
+I = I_0 \cos^2\left(\frac{\pi \Delta y}{\lambda}\right)
+$$
+
+Where:
+- $ I_m $ = intensity at the $ m $-th fringe
+- $ I_0 $ = maximum intensity (at the central maximum)
+- $ m $ = fringe order (1st, 2nd, etc.)
+- $ \Delta y $ = path difference
+- $ D $ = distance from the slits to the screen
+
+### Summary:
+- The **path difference** is the difference in the distances traveled by the two light waves from the slits to a point on the screen.
+- If the path difference is a whole multiple of the wavelength, you get **constructive interference** (bright fringe), and if it's an odd multiple of half the wavelength, you get **destructive interference** (dark fringe).
+- The **fringe width** depends on the wavelength and the geometry of the setup and can be calculated using:
+
+  $$ 
+  \beta = \frac{\lambda D}{d}
+  $$
+
+  Where:
+  - $ \beta $ = fringe width (distance between adjacent fringes)
+  - $ \lambda $ = wavelength of the light
+  - $ D $ = distance from the slits to the screen
+  - $ d $ = distance between the two slits
+
+## Final equations
+
+Time to combine everything together. We'll continue to use the variable definitions from above, but include $y_m$, or the distance between the center, $m=0$ and some bright fringe of order $m$. When calculating, it can also be assumed that (for small angles) $\sin\theta\approx\theta$.
+
+$$
+\boxed{d\sin\theta=m\lambda}
+$$
+
+$$
+\boxed{y_md=Dm\lambda}
+$$