double slit
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2025-01-30 00:38:52 -06:00
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@@ -430,3 +430,88 @@ The sign conventions depend on whether the observer and source are moving toward
In the case of light, the relativistic Doppler shift formula is used, where the frequency shift is influenced by both the motion and the speed of light.
The Doppler Effect explains phenomena such as the change in pitch of a passing car or the redshift/blueshift observed in the light from stars and galaxies.
Sure! Here's a combined explanation of the **path difference** in the double-slit experiment, with the math expressed using LaTeX notation:
---
# Young's Experiment
In the **double-slit experiment**, light passes through two slits and creates an interference pattern on a screen. The **path difference** refers to the difference in the distances that the light waves travel from each of the two slits to a particular point on the screen.
### What is Path Difference?
1. **Two light waves** are emitted from the two slits, and they travel towards a point on the screen.
2. The distance traveled by the light from the first slit to that point is different from the distance traveled by the light from the second slit.
3. The **path difference** is simply the difference between these two distances.
### How Path Difference Affects the Interference Pattern:
- **Constructive Interference**: This occurs when the path difference is a **whole number multiple** of the wavelength, i.e.,
$$
\Delta y = m\lambda \quad \text{(where $m$ is an integer)}
$$
In this case, the waves arrive **in phase** and interfere **constructively**, creating a **bright fringe** on the screen.
- **Destructive Interference**: This happens when the path difference is an **odd multiple** of half the wavelength, i.e.,
$$
\Delta y = \left( m + \frac{1}{2} \right) \lambda \quad \text{(where $m$ is an integer)}
$$
Here, the waves arrive **out of phase** and interfere **destructively**, resulting in a **dark fringe**.
### Formula for Path Difference:
In the double-slit experiment, the path difference for a point on the screen at an angle \( \theta \) can be expressed as:
$$
\Delta y = d \sin \theta
$$
Where:
- $ \Delta y $ = path difference
- $ d $ = distance between the two slits
- $ \theta $ = angle between the central maximum (the center of the pattern) and the point on the screen
- $ \lambda $ = wavelength of the light
At the **central maximum** (the middle bright fringe), the path difference is zero because the light from both slits travels the same distance. As you move away from the center, the path difference increases, affecting the type of interference (constructive or destructive) at each point on the screen.
### How Path Difference Relates to Intensity:
The intensity of the light at a point on the screen in the double-slit experiment depends on the path difference. The intensity for constructive and destructive interference can be written as:
For constructive interference (bright fringes):
$$
I_m = I_0 \cos^2\left(\frac{m\pi d}{\lambda D}\right)
$$
For destructive interference (dark fringes):
$$
I = I_0 \cos^2\left(\frac{\pi \Delta y}{\lambda}\right)
$$
Where:
- $ I_m $ = intensity at the $ m $-th fringe
- $ I_0 $ = maximum intensity (at the central maximum)
- $ m $ = fringe order (1st, 2nd, etc.)
- $ \Delta y $ = path difference
- $ D $ = distance from the slits to the screen
### Summary:
- The **path difference** is the difference in the distances traveled by the two light waves from the slits to a point on the screen.
- If the path difference is a whole multiple of the wavelength, you get **constructive interference** (bright fringe), and if it's an odd multiple of half the wavelength, you get **destructive interference** (dark fringe).
- The **fringe width** depends on the wavelength and the geometry of the setup and can be calculated using:
$$
\beta = \frac{\lambda D}{d}
$$
Where:
- $ \beta $ = fringe width (distance between adjacent fringes)
- $ \lambda $ = wavelength of the light
- $ D $ = distance from the slits to the screen
- $ d $ = distance between the two slits