springs
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\sum{\vec{F}}=\langle ma+mg;-\tfrac{\pi}{2}\rangle
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\sum{\vec{F}}=\langle ma+mg;-\tfrac{\pi}{2}\rangle
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$$
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$$
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# Springs
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Springs are explained by something called *Hooke's Law*. It essentially states:
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> Ut tensio sic vic[^2]
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That translates to:
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> As extension, so is force
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$$
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\therefore \Delta x \propto F
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$$
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The actual formula looks like:
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$$
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\vec{F}_e=-k\Delta x
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$$
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The subscript $e$ means 'the elastic force' or the force being exerted *by* the spring. That wording is hyper-specific for a reason, that reason being the slight distinction between the signs of the force vectors while the spring is in different states. As you'll see in the diagram below, a positive $\Delta x$ signifies an extension of the spring, which generates a negative force. The exact opposite is true in any other case.
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Like in any other problem of proportionality (in math), $k$ is taken to be the *constant* value of the proportion. The SI unit for the **spring constant** is Newtons per meter. Therefore, it is possible using simple algebra to show:
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$$
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k=\frac{||\vec{F}||}{x}
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$$
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[^1]: I'm working in radians here.
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[^1]: I'm working in radians here.
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[^2]: This is latin.
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#physics
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#physics
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