thermo stuff
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@@ -65,5 +65,29 @@ $$
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\lambda_{\text{peak}}=\frac{b}{T}
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\lambda_{\text{peak}}=\frac{b}{T}
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$$
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$$
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Where $b$ is Wien's displacement constant, equal to $2.897771955\cdot 10^{-3} \mathrm{m}\cdot\mathrm{K}$.
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Where $b$ is Wien's displacement constant, equal to $2.897771955\cdot 10^{-3} \mathrm{m}\cdot\mathrm{K}$.
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> [!NOTE]
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> The material does not matter. All black bodies emit radiation over all wavelengths.
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## Stefan Boltzmann Law of Radiation
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This law describes the emissive power of a Black Body per unit area.
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$$
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E_b=\varepsilon \sigma\cdot T^4
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$$
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In the above equation,:
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- $E_b$ is the **Emissive Power** of a black body, per unit time, per unit area.
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- $\varepsilon$ is the emissivity of an object
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- $\sigma$ is the Boltzmann constant, about $\approx 5.670374419\cdot 10^{-8} \mathrm{W}\cdot\mathrm{m}^{-2}\cdot \mathrm{K}^{-4}
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- A perfect black body has an emissivity of $1$, and an albedo of $0$
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- always work in default SI units
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If you desire the total power across the entirety of the surface:
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$$
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P_b=A\varepsilon \sigma\cdot T^4
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$$
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Where $A$ is the area of the exposed surface.
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