thermo stuff

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2024-11-17 17:18:58 -06:00
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@@ -65,5 +65,29 @@ $$
\lambda_{\text{peak}}=\frac{b}{T}
$$
Where $b$ is Wien's displacement constant, equal to $2.897771955\cdot 10^{-3} \mathrm{m}\cdot\mathrm{K}$.
Where $b$ is Wien's displacement constant, equal to $2.897771955\cdot 10^{-3} \mathrm{m}\cdot\mathrm{K}$.
> [!NOTE]
> The material does not matter. All black bodies emit radiation over all wavelengths.
## Stefan Boltzmann Law of Radiation
This law describes the emissive power of a Black Body per unit area.
$$
E_b=\varepsilon \sigma\cdot T^4
$$
In the above equation,:
- $E_b$ is the **Emissive Power** of a black body, per unit time, per unit area.
- $\varepsilon$ is the emissivity of an object
- $\sigma$ is the Boltzmann constant, about $\approx 5.670374419\cdot 10^{-8} \mathrm{W}\cdot\mathrm{m}^{-2}\cdot \mathrm{K}^{-4}
- A perfect black body has an emissivity of $1$, and an albedo of $0$
- always work in default SI units
If you desire the total power across the entirety of the surface:
$$
P_b=A\varepsilon \sigma\cdot T^4
$$
Where $A$ is the area of the exposed surface.