From e814e428a96a7c6edd53496bfb02c4f17f2a94cd Mon Sep 17 00:00:00 2001 From: Krishna Date: Mon, 26 Aug 2024 21:38:46 -0500 Subject: [PATCH] fixing subscripts --- content/physics/kinematics.md | 2 +- 1 file changed, 1 insertion(+), 1 deletion(-) diff --git a/content/physics/kinematics.md b/content/physics/kinematics.md index 567074f..5a8b864 100644 --- a/content/physics/kinematics.md +++ b/content/physics/kinematics.md @@ -127,7 +127,7 @@ This can also be visually represented as such: You can also calculate the square of the velocity vector independent of of the time $t$. This can low-key be helpful when you only have the position vector $\vec{s}$. $$ -\vec{v^2}=\langle v^2_x0+2a_x(x-x_0),v^2_y0+2a_y(y-y_0) \rangle +\vec{v^2}=\langle v^2_{x0}+2a_x(x-x_0),v^2_{y0}+2a_y(y-y_0) \rangle $$ The position finally being: $$